Question

A car is moving with a velocity of 40km/hr. Its velocity is reduced to 20 km/hr after covering a distance of 200m. Calculate the retardation.​

Answer 1

GIVEN

INITIAL VELOCITY(u)=40KM/H=100/8 m/S

FINAL VELOCITY(v)=20km/h=50/9 m/S

DISTANCE(S)=200M

ACCELERATION/RETARDATION(a) =?

ACCORDING THIRD EQUATION OF MOTION:

${v}^{2} - {u}^{2} = 2as$

PUT VALUE

${ (\frac{100}{9} )}^{2} - {( \frac{50}{9}) }^{2} = 2 \times a \times 200$

$\frac{10000}{81} - \frac{2500}{81} = 400 \times a$

$\frac{10000 - 2500}{400 \times 81} = a$

$a = \frac{75}{324} m \: per \: {sec}^{2}$

TO CHANGE METRE INTO CENTIMETRE :

$a = \frac{75}{324} \times 100$

$a = 23.15 \: cm \: {sec}^{2}$

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