Question

a car is moving with a velocity of 80m/s the driver applies brakes to produce an uniform acceleration of -2m/s² how will the car go before it stop
v=80m/sec
a=-2m/sec
v²=,v²-2m²
s=?
=0 final velocity ​

Answer 1

Answer:

v²-u²=2as

use this u get urs answer perfectly

Answer 2

Therefore the distance traveled by car before coming to rest is 1600 m.

Given:

Initial velocity of the car = 80 m/s

Uniform deceleration ( brakes applies ) of the car = -2 m/s²

To Find:

The distance traveled by car after applying brakes.

Solution:

The given question can be solved very easily as shown below.

Given that,

Initial velocity of the car = u = 80 m/s

Uniform deceleration ( brakes applies ) of the car =a = -2 m/s²

As the brakes are applied, the final velocity = v = 0 m/s

By the equations of kinematics,

⇒ v² - u² = 2as

Where s is the distance traveled by car.

⇒ 0 - 80² = 2 × (-2) × s

⇒ -6400 = -4s

⇒ s = 6400/4 = 1600 m

Therefore the distance traveled by car before coming to rest is 1600 m.

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