Question

A car is moving with a velocity of 90km/hr and it applies break., after break car moves around 6m.Find the retardation of car​

Answer 1

Given :

• Initial velocity, u = 90 km/h
• Final velocity, v = 0 m/s (as it applies brakes)
• Distance travelled, s = 6 m

To find :

• The retardation of car, a

According to the question,

Note :-

We need to change the Initial velocity in m/s,

• Initial velocity, u = 25 m/s

➞ v² = u² + 2as [Third equation of motion]

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• s = Distance

➞ Substituting the values,

➞ (0)² = (25)² + 2 × a × 6

➞ 0 = 625 = 12a

➞ 0 - 625 = 12a

➞ - 625 ÷ 12 = a

➞ - 52.0833 = a

• So, the retardation of car is 52.0833 m/s².

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