A car is moving with a vilocity of 90 km/h appling breaks it takes 10 sec to come on rest how far car will cover in 10 sec
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With linear deceleration from 90-0, the distance would be exactly half what it would have travelled at 90km/hr, which is (on average) 45km/hr for 10 seconds. 10 sec. divided by 3600 sec/hr multiplied by 45,000 meters = 125 meters.
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2
Answer:
With linear deceleration from 90-0, the distance would be exactly half what it would have travelled at 90km/hr, which is (on average) 45km/hr for 10 seconds. 10 sec. divided by 3600 sec/hr multiplied by 45,000 meters = 125 meters.
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