A car is moving with at a velocity if 45 km/hr. The driver applies the brakes and the car comes to rest in 3 second. What is its retardation? How far does it move before coming to rest?
Answers
Answered by
16
Initial speed u = 45 km/h = 12.5 m/s,
Final speed v = 0 m/s,
time t = 3 s,
acceleration a.
v = u + at=> 0
= 12.5 + a(3)
a= -(12.5/3)
= -4.17 m/s^2.
Retardation = 4.17 m/s^2.
Distance travelled d = (1/2)(12.5)(3) = 18.75 m.
Final speed v = 0 m/s,
time t = 3 s,
acceleration a.
v = u + at=> 0
= 12.5 + a(3)
a= -(12.5/3)
= -4.17 m/s^2.
Retardation = 4.17 m/s^2.
Distance travelled d = (1/2)(12.5)(3) = 18.75 m.
Similar questions