Question

A car is moving with constant acceleration crosses two points A and B with velocities 10m/s and 20m/s
.Find the velocity of the car midway between A and B

Answer 1

Answer:

Velocity of the car at midway between A and B is 25.5 m/s.

Explanation:

Given:

Initial velocity (u) = 20 m/s

Final velocity (v) = (20+10) m/s

= 30 m/s

Let the acceleration be 'a' m/s²,

and the distance be 's' m.

A.T.Q.

From the third equation of motion;

V² - U² = 2as

[Case 1]

30² - 20² = 2as

900 - 400 = 2as

500 = 2as .........(i)

[Case 2]

V² - 20² = 2as/2

V² - 400 = 500/2 {:.2as = 500}

V² - 400 = 250

V² = 250 + 400

V² = 650

V = √650

V = 25.495

V ~ 25.5

Thus, Velocity of the car at midway is approximately equal to 25.5 m/s.