Question

A car is moving with initial velocity 2m/s and acceleration 4 m/s2.Find the distance travelled by the car in 9 th second

Answer 1

Question - If a body is moving with an initial velocity of 3m/s and an acceleration of 2m/s, then what will be the distance travelled by the 4th second?

Answer - When t=4

s= ut+ 0.5 x at^2

s= 3 x 4+ 0.5 x 2 x 4^2

s= 12+ 16

s= 28 m

When t=3

s= ut+ 0.5 x at^2

s= 3 x 3+ 0.5 x 2 x 3^2

s= 9+ 9

s= 18 m

Answer 2

Answer:

When t=4

s= ut+ 0.5 x at^2

s= 3 x 4+ 0.5 x 2 x 4^2

s= 12+ 16

s= 28 m

When t=3

s= ut+ 0.5 x at^2

s= 3 x 3+ 0.5 x 2 x 3^2

s= 9+ 9

s= 18 m

Thus the distance travelled in the 4th second= Total distance in 4 seconds- Total distance in 3 seconds

= 28–18

= 10 m

Explanation:

this answer may be wrong but formula is same