Question

A car is moving with initial velocity 'U' m/s. After applying the brakes its retardation is 1m/sand it
stopped after 24 secs, find initial velocity and distance travelled by the car after applying the brakes?​

Answer 1

Given :-

• A car is moving with initial velocity 'u' m/s. After applying the brakes its retardation is 1m/s² and it stopped after 24 sec.

To Find :-

• Initial Velocity = ?
• Distance travelled by the car after applying the brakes = ?

Solution :-

• Retardation (a) = -1 m/s²
• Time (t) = 24 seconds
• Final Velocity (v) = 0 m/s

By using first equation of motion we get :

• v = u + at

Substituting the given values in above equation we get :

➻ 0 = u + (-1) × 24

➻ -u = -24

➻ u = 24 m/s

Now, let's find the distance travelled by the car after applying the brakes :

By using third equation of motion we get :

→ v² - u² = 2as

→ (0)² - (24)² = 2(-1)s

→ 0 - 576 = -2s

→ s = -576 ÷ -2

→ s = 576 ÷ 2

→ s = 288 m

Hence,

• Initial Velocity = 24 m/s
• Distance travelled by the car after applying the brakes = 288 m

Answer 2

Explanation:

QUESTION:-

A car is moving with initial velocity 'U' m/s. After applying the brakes its retardation is 1m/sand itstopped after 24 secs, find initial velocity and distance travelled by the car after applying the brakes?

ANSWER :-

Final velocity v=0

Using v=u+at

So, 0=u+(−0.5)×12

⟹ u=6 m/s

Using, v 2 −u 2 =2aS

Or, 0−6 ^2

=2×(−0.5)×S

⟹ S=36 m

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@TheStellar♥️