Question

A car is moving with speed of 20m/s, Find distance travelled by car 1/2 hour​

Answer 1

Answer:

This is your answer

Explanation:

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Answer 2

Answer:

Given,

Speed=20m/s,d=50m,retardation=5m/s

2Let the ppossible reaction time be ts So the car moves 20tm And applied breaks with retardation 5m/s

2So, the total distance under retardation is ≤50m

Thus the distance under the application of retardation = 2×520 2 −0 2 =s ′⇒s =40m

Therefore, 20t

s +40≤=50⇒20t

s ≤50−40⇒20t

s =10⇒t

s ≤ 21 ≤0.5s