Question

a car is moving with speed of 56 km/h is brought to rest by applying brakes in 10 sec find its accelartion​

Answer 1

Answer:

-5.6

Step-by-step explanation:

Given :- u= 56km/h

v = 0 km/h

time = 10sec

since , v = u + at

0 = 56 + a * (10)

a = -56/10 = -5.6Answer

Hope it's helpful

Answer 2

$\large \green {\underline {\underline {\bf Given}} : - }$

➝ Initial Velocity, u = 56m/s

➝ Final Velocity, v = 0m/s

➝ Time, t = 10sec

$\large \green {\underline {\underline {\bf To\: find }} : - }$

➝ Acceleration of the car

$\Large \orange{ \underline{ \underline{\bf Solution}} : - }$

using 1st equation of motion,

that is

$\longrightarrow \sf v = u + at$

$\longrightarrow \sf 0 = 56 + a \times 10$

$\longrightarrow \sf a = \cancel \frac{ - 56}{10}$

$\longrightarrow \sf a = - 5.6 {ms}^{ - 2}$

Hence, acceleration is -5.6m/s²