Question

a car is moving with speed of 90km/h by applying brakes with in 32m durniny brake find the acceleration tratandation​

Answer 1

Explanation:

given,

speed [u]=90km/h=25.5m/s

distance [s]=32m

[v]=0m/s

distance [s]=32m [v]=0m/s [a]=?

[by using 3rd equation of motion v^2-u^2=2as]

(0)^2-(25.5)^2=2 X a X 32

650.25=64a

650.25=64a a=65.25/64

650.25=64a a=65.25/64 a=1.01

the acceleration tratandation is 1.01m/s^2

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