Question

A car is moving with the acceleration 2m/s^2 along a straight line. The distance travelled in first 4 seconds.

Answer 1

Explanation:

use

s=ut+1/2 at^2

where u is intial velocity=0

so s= 1/2 ×2×16=16

Answer 2

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As we know that,

S = ut + 1/2at^2 . . . . . . . . . 1

Here, a =2 m/s^2 , u = 0 (as the car starts from rest)

And t = 4 sec.

From equation 1

S = 0 + 1/2×2×4×4

S = 16 m

Now we also know that,

V^2 = u^2 + 2aS

V^2 = 2aS ( as u =0 )

V^2 = 2×2×16

V^2 = 64

V = (64)^1/2

V = 8 m/s