Question

A car is moving with the acceleration 2m/s^2 from rest. Find the distance traveled by the car in 10 th second???​

Answer 1

Answer:

Explanation:

From the Question,

Given :-

Initial Velocity (u) = 0m/s

Acceleration (a) = 2 m/s²

To find  :-

Distance travelled in the 10th second (n = 10s)

Distance travelled in nth second is given by :

$\boxed{\boxed{\sf s_n = u + \dfrac{a}{2}(2n - 1)}}$

Putting n = 10s,

$\longrightarrow \sf s_{10} = 0 + \dfrac{2}{2}([2(10) - 1] \\ \\ \longrightarrow \sf s_{10} = 20 - 1 \\ \\ \huge{\longrightarrow \sf s = 19 \ m}$

Thus, the distance travelled in the 10th second is 19 m.

Answer 2

$</p><p>\tt{\huge{\pink{Hello!!! }}}$

$\tt {\red {\huge {\boxed {\boxed {\bullet{Question \: - }}}}}}$

A car is moving with the acceleration 2m/s^2 from rest. Find the distance traveled by the car in 10 th second???

The car is innitally at rest.

$\tt {\green {\huge {\boxed {\boxed {\bullet{Solution \: - }}}}}}$

$\tt {\blue { Given \: - }}$

From the question we can infer that :

• U = 0

• Acceleration = 2 m/s^2

• T = 10 sec

• S = ?

$\tt {\pink{--------}}$

By Second Equation Of Motion ,

$</p><p>\mathfrak{\huge{\boxed{\boxed{\underline{\purple{\implies{S \: = \: ut\:+ \dfrac{1}{2} a {t}^2 }}}}}}}$

$\tt{\purple{\therefore{S_{10} \: = \: \dfrac{1}{2} \times 2 \times {10}^2 \: =\: 100 \:m. }}}$

$\tt{\purple{\therefore{S_{9} \: = \: \dfrac{1}{2} \times 2 \times {9}^2 \: =\: 81 \:m. }}}$

Distance Travelled in the 10th Sec :

$\tt{\blue{\implies{D_{10} = S_{10} - S_{9} =( 100 - 81 ) \: m = 19 \: m. }}} ...........(A)$