Question

A car is moving with the acceleration 2m/s from rest. find the distance travelled by the car in the 5thsecond ​

Answer 1

Given

• Initial Velocity = 0 m/s
• Acceleration = 2 m/s²
• Time = 5 sec

To Find

• Distance covered by the car

Solution

● Here we would be using the second equation of motion, that is, s = ut+½at²

✭ Distance Covered :

→ s = ut+½at²

• s = Distance = ?
• u = Initial Velocity = 0 m/s
• t = Time = 5 sec
• a = Acceleration = 2 m/s²

→ s = 0 × 5 + ½ × 2 × 5²

→ s = 0 + 5²

→ s = 0 + 25

→ s = 25 m

∴ The distance covered by the body in 5 seconds is 25 m

Answer 2

Given:-

$\bullet$A car is moving with the acceleration 2 m/s from rest

To Prove:-

$\bullet$Find the distance travelled by the car in the 5 th second

Solution:-

$\bullet$Using formula,

$\\ \leadsto{ \boxed{ \boxed{ \boxed{ \bold{s_n =u + \frac{a}{t} \: (2n - 1)}}}}}$

$\bullet$Substitute the value given in the question...

$\\ \leadsto{ \boxed{ \boxed{ \boxed{ \bold{s_1 \: _0 =0 + \frac{2}{2} \: (2 \times 5 - 1)}}}}}$

$\\ \leadsto{ \boxed{ \boxed{ \boxed{ \bold{s_1 \: _0 =10 - 1}}}}}$

$\\ \leadsto{ \boxed{ \boxed{ \boxed{ \bold{ \blue{s_1 \: _0 =9 \: m}}}}}}$

$\bullet$The distance travelled by 5 th second is 9 m