Physics, asked by mohammadshaikshavali, 3 months ago

A car is moving with the acceleration 2m/s from rest. find the distance travelled by the car in the 5thsecond ​

Answers

Answered by Anonymous
29

AnswEr :

›»› The distance travelled by the car in the 5 second is 25 m.

Given :

  • Initial velocity of car = 0 m/s.
  • Acceleration produced by car = 2 m/s².
  • Time taken by car = 5 second.

To Find :

  • Distance travelled by the cat in the 5 second = ?

Solution :

As we are given with the initial velocity of car, acceleration produced by car, and time taken by the car so, we will use the second equation of motion, that is,

s = ut + ½ at².

Here,

  • s is the Distance travelled in m.
  • u is the Initial velocity in m/s.
  • t is the Time taken in second.
  • a is the Acceleration in m/s².

Substituting the given values in the equation, we get :

→ s = 0 * 5 + ½ * 2 * (5)²

→ s = 0 + ½ * 2 * (5)²

→ s = 0 + ½ * 2 * 25

→ s = 0 + 1 * 25

→ s = 0 + 25

s = 25

Hence, the distance travelled by the car in the 5 second is 25 m.

Extra Brainly Knowledge :

★ Three equations of motion :

First equation of motion :

  • v = u + at.

Second equation of motion :

  • s = ut + ½ at².

Third equation of motion :

  • v² = u² + 2as.
Answered by Mayura24
8

Answer:

Given:-

  • A car is moving with the acceleration 2 m/s from rest and time taken is 5 secs.

To Find:-

  • What is the distance traveled by the car in the 5 second.

Solution:-

Given in the question that is,

u = 0 m/s

a = 2 m/s

☛ t = 5 second

Now, we have to use formula that is,

✪ s = ut + \dfrac{1}{2}at² ✪

⇰ s = 0(5) + \dfrac{1}{2} × (2)(5)²

⇰ s = 0 + \dfrac{1}{2} × 2 × 25

⇰ s = 0 + 25

s = 25 m

Therefore, the distance traveled by the car in the 5 second is 25 m .

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