A car is moving with the acceleration 2m/s from rest. find the distance travelled by the car in the 5thsecond
Answers
AnswEr :
›»› The distance travelled by the car in the 5 second is 25 m.
Given :
- Initial velocity of car = 0 m/s.
- Acceleration produced by car = 2 m/s².
- Time taken by car = 5 second.
To Find :
- Distance travelled by the cat in the 5 second = ?
Solution :
As we are given with the initial velocity of car, acceleration produced by car, and time taken by the car so, we will use the second equation of motion, that is,
→ s = ut + ½ at².
Here,
- s is the Distance travelled in m.
- u is the Initial velocity in m/s.
- t is the Time taken in second.
- a is the Acceleration in m/s².
Substituting the given values in the equation, we get :
→ s = 0 * 5 + ½ * 2 * (5)²
→ s = 0 + ½ * 2 * (5)²
→ s = 0 + ½ * 2 * 25
→ s = 0 + 1 * 25
→ s = 0 + 25
→ s = 25
Hence, the distance travelled by the car in the 5 second is 25 m.
Extra Brainly Knowledge :
★ Three equations of motion :
First equation of motion :
- v = u + at.
Second equation of motion :
- s = ut + ½ at².
Third equation of motion :
- v² = u² + 2as.
Answer:
Given:-
- A car is moving with the acceleration 2 m/s from rest and time taken is 5 secs.
To Find:-
- What is the distance traveled by the car in the 5 second.
Solution:-
Given in the question that is,
☛ u = 0 m/s
☛ a = 2 m/s
☛ t = 5 second
Now, we have to use formula that is,
✪ s = ut + at² ✪
⇰ s = 0(5) + × (2)(5)²
⇰ s = 0 + × 2 × 25
⇰ s = 0 + 25
⇰ s = 25 m
Therefore, the distance traveled by the car in the 5 second is 25 m .