Question

A car is moving with the acceleration 2m/sfrom rest. find the distance travelled by the car in the 5th second ​

Answer 1

Given :-

A car is moving with the acceleration 2 m/s from rest.

To Find :-

The distance traveled by the car in the 5th second.

Solution :-

We know that,

• t = Time
• u = Initial velocity
• a = Acceleration

Let the distance traveled in 5th s be 'n'.

By the formula,

$\underline{\boxed{\sf s_n=u+\dfrac{a}{t} (2n-1)}}$

Given that,

Acceleration (a) = 2 m/s²

Initial velocity (u) = 0 m/s (Since the car is initial rest)

Substituting their values,

s₁₀ = 0 + 2/2 [2(5) - 1]

s₁₀ = 10 - 1

s = 9

Therefore, the distance traveled by the car in the 5th second is 9 m.

Answer 2

Answer:

Given :-

A car is moving with the acceleration 2 m/s from rest.

To Find :-

The distance traveled by the car in the 5th second.

Solution :-

We know that,

t = Time

u = Initial velocity

a = Acceleration

Let the distance traveled in 5th s be 'n'.

By the formula,

\underline{\boxed{\sf s_n=u+\dfrac{a}{t} (2n-1)}}

s

n

=u+

t

a

(2n−1)

Given that,

Acceleration (a) = 2 m/s²

Initial velocity (u) = 0 m/s (Since the car is initial rest)

Substituting their values,

s₁₀ = 0 + 2/2 [2(5) - 1]

s₁₀ = 10 - 1

s = 9

Therefore, the distance traveled by the car in the 5th second is 9 m.