A car is moving with the speed of 40 km per hour and car b is moving with a speed of 60 km per hour along parallel straight path starting from the same point what is the position of car a with respect to kabali after 15 minutes
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Answer:
The car b is 5 km ahead of car a after 15 minutes.
Explanation:
Given that,
Speed of car a v_{a}=40\ km/h
Speed of car b v_{b}=60\ km/h
Time t = 15 min= 0.25 h
The distance traveled by the cars is related to the time and their respective velocities as:
v_{a}=\dfrac{d_{a}}{t}
For car a,
d_{a}=40\times0.25
d_{a}=10\ km
For car b,
d_{b}=60\times0.25
d_{b}=15\ km
The distance between car a and car b is
d=d_{b}-d_{a}
d =15-10
d = 5\ km
Hence, The car b is 5 km ahead of car a after 15 minutes.
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