Physics, asked by exoticbeauty9976, 11 months ago

A car is moving with the speed of 40 km per hour and car b is moving with a speed of 60 km per hour along parallel straight path starting from the same point what is the position of car a with respect to kabali after 15 minutes

Answers

Answered by krishtiwari07
0

Answer:

The car b is 5 km ahead of car a after 15 minutes.

Explanation:

Given that,

Speed of car a v_{a}=40\ km/h

Speed of car b v_{b}=60\ km/h

Time t = 15 min= 0.25 h

The distance traveled by the cars is related to the time and their respective velocities as:

v_{a}=\dfrac{d_{a}}{t}

For car a,

d_{a}=40\times0.25

d_{a}=10\ km

For car b,

d_{b}=60\times0.25

d_{b}=15\ km

The distance between car a and car b is

d=d_{b}-d_{a}

d =15-10

d = 5\ km

Hence, The car b is 5 km ahead of car a after 15 minutes.

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