a car is moving with the uniform acceleration of 10 m/s2 for 10 seconds starting from rest.Then the body moves with constant velocity for next 5 seconds. find the distance travelled by the body
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over the first 10 sec.
a = 10 m/sec^2 t = 10 s u = 0 m/s
v = u + at = 0 + 10 * 10 = 100 m/s
s1 = ut + 1/2 at^2 = 1/2 * 10 * 10^2 = 500 m
over the next 5 sec.
s2 = v t = 100 * 5 = 500 m
Total distance = 1, 000 m
a = 10 m/sec^2 t = 10 s u = 0 m/s
v = u + at = 0 + 10 * 10 = 100 m/s
s1 = ut + 1/2 at^2 = 1/2 * 10 * 10^2 = 500 m
over the next 5 sec.
s2 = v t = 100 * 5 = 500 m
Total distance = 1, 000 m
Answered by
1
velocity after 10s is a×t=10×10=100m/s
distance travelled with acceration is ut+1/2at2
=0+1/2×10×10×10=500m
distance travelled with constant velocity is vt
= 100×5=500
total distance =500+500=1000m
distance travelled with acceration is ut+1/2at2
=0+1/2×10×10×10=500m
distance travelled with constant velocity is vt
= 100×5=500
total distance =500+500=1000m
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