Physics, asked by negiseema678, 7 months ago

. A car is moving with uniform velocity 40 m/sec.It is stopped in 4 sec by applying a force of 1300 Newton through its brakes.calculate (a) change in momentum(b)retardation of car(c)the mass of car.​

Answers

Answered by pokharelshrisha
0

Answer:

soln: here

given:

initial velocity(u)= 40m/s

final velocity(v) = 0 m/s  [ the sudden apply of the brake cause the final velocity to be 0.]

force applied(f) = 1300 N

time taken(t) = 4s

now,

a) change in momentum= be x

we know that,

F= change in momentum/time

or, 1300= x/4

or, 1300*4 = x

so, x= 5200 kg*m/s

b) retardation of the car(a)=

a= (v-u)/t

or, a= 0-40/4

so, a= -10

∴ retardation of teh car= 10 m/s^2 [ no need to write -10m/s^2 as retardation already means negative acceneration.]

c) the mass of the car=

we know that,

F= ma

or, 1300= m* (-10)

or, 1300/ (-10)= m

∴ mass of the car(m)= -130 kg

Explanation:

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