. A car is moving with uniform velocity 40 m/sec.It is stopped in 4 sec by applying a force of 1300 Newton through its brakes.calculate (a) change in momentum(b)retardation of car(c)the mass of car.
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Answer:
soln: here
given:
initial velocity(u)= 40m/s
final velocity(v) = 0 m/s [ the sudden apply of the brake cause the final velocity to be 0.]
force applied(f) = 1300 N
time taken(t) = 4s
now,
a) change in momentum= be x
we know that,
F= change in momentum/time
or, 1300= x/4
or, 1300*4 = x
so, x= 5200 kg*m/s
b) retardation of the car(a)=
a= (v-u)/t
or, a= 0-40/4
so, a= -10
∴ retardation of teh car= 10 m/s^2 [ no need to write -10m/s^2 as retardation already means negative acceneration.]
c) the mass of the car=
we know that,
F= ma
or, 1300= m* (-10)
or, 1300/ (-10)= m
∴ mass of the car(m)= -130 kg
Explanation:
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