Question

A car is moving with velocity 20m per second after applying the break it's stops after 2 s . Find the acceleration and distance​

Answer 1

Answer:

Initial velocity = 20 m/s

Final velocity = 0 m / s

Time = 2 seconds

Acceleration= v - u / t

= 0 - 20 / 2

= - 10 m/s^2

Distance = (By second equation of motion)

s = ut + 1/2 at^2

s = 20*2 + 1/2 * (-10)*(2)^2

s = 20 m/s

Here, the initial velocity has been taken according to the question, final velocity has been taken 0 as brakes are applied. 'v' stands for final velocity and 'u' for the initial velocity. Here, you can also say that the acceleration is -10 m/s or retardation is 10 m/s, one and the same thing.

Hope you found my answer helpful!

Thanks !

Answer 2

Answer:

Explanation:

α = β - β₀ / T = Δv/Δt.

20-0/2 = 20/2 = 10 (Acceleration).

Distance = 2×10⁻².