A car is moving with velocity of 2m/s . when the driver applied brake, it come to rest by 4 second
a) what is the velocity of the car when it come to rest?
b) calculate the deceleration of the car
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Answer:
a is 0 and b is 0.5m/s^2
Explanation:
initial velocity,u = 2m/s
final velocity , V=0m/s(since the car has stopped its not moving)
time ,t = 4 sec
From first equation of motion,
v=u + at
0=2 + (-a)t( force is retarding)
0 = 2 -at
0 =2 - 4a
4a = 2
a = 1/2
a = 0.5 m/s^2
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