Question

A car is parked at the roadside. A truck passes by it, at a speed of 5m/s. What would be the speed at which the image of the car appears to move away from the truck, as viewed in the rear-view mirror of the truck?

Answer 1

Explanation:

In a plane mirror, the object and its image always remain at the same distance from the mirror. So, when the car reverses at a speed of , 5then the image will also appear to move towards the driver will be 5 + 5=10

Answer 2

Answer:

The correct answer will be -

It will appear to be moving at a speed of 10 m/s.

Explanation:

Correction in the question -

The given rear-view mirror should be a plane mirror in this question. But in general, these are convex mirrors.

Given in the question -

• A car is parked at the roadside.
• A truck passes by it, at a speed of 5m/s.

O - object

M - mirror

I - Image

Since it is a plane mirror -

$V_{OM} = -V_{IM}$

so,

$V_O-V_M = V_M-V_I\\\\V_I = 2V_M-V_O$

Since $V_M$ will be 5 m/s as it is viewed from a moving truck.

$V_I = 2\times 5 = 10\ m/s$

So it will appear to be moving with a speed of 10 m/s.

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