Question

A car is pulled with a force of 60.N at angle of 37 from the
horizontal. Find the vertical and horizontal components of the applied force​

Answer 1

Answer:

                                   60o  |  

                                          |      

                                          |   Fy  (the vert. comp.)  

                                          ↑

←  30o                                 |    

                  Fx  (the horizontal componenet)                        

                                       

F = √(Fx2 + Fy2)        

Fy = 50 · cos 60o = 50 · (1/2) = 25 N  

Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N    

I see, that vector sign did not appear in my comment above, so the vector equation is  

→                        →                      →        

 F  =  50  cos 30o  i   +  50 cos 60o  j

Answer 2

Answer:

the vertical compo is 71.8 and the horizontal compo is 54

Explanation:

thank you