Question

a car is purchased for rs348000 its value depricates at 10 percent per annum during the first year and at 20 percent per annum during second year what will be its value after 2 years​

Answer 1

Answer:

The value of the car after two years is Rs 250560.

Step-by-step explanation:

Initial value of the car, P= Rs 348000

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue = P×1-p100×1-q100

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue = P×1-p100×1-q100=Rs. 348000×1-10100×1-20100

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue = P×1-p100×1-q100=Rs. 348000×1-10100×1-20100=Rs. 348000×100-10100×100-20100

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue = P×1-p100×1-q100=Rs. 348000×1-10100×1-20100=Rs. 348000×100-10100×100-20100=Rs. 348000×90100×80100

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue = P×1-p100×1-q100=Rs. 348000×1-10100×1-20100=Rs. 348000×100-10100×100-20100=Rs. 348000×90100×80100=Rs. 348000×910×810

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue = P×1-p100×1-q100=Rs. 348000×1-10100×1-20100=Rs. 348000×100-10100×100-20100=Rs. 348000×90100×80100=Rs. 348000×910×810=Rs. 3480×9×8=Rs. 250560∴

Initial value of the car, P= Rs 348000Rate of depreciation for the first year, p= 10%Rate of depreciation for the second year, q= 20%Time, n = 2 years.Then the value of the car after two years is given byValue = P×1-p100×1-q100=Rs. 348000×1-10100×1-20100=Rs. 348000×100-10100×100-20100=Rs. 348000×90100×80100=Rs. 348000×910×810=Rs. 3480×9×8=Rs. 250560∴ The value of the car after two years is Rs 250560.

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