a car is retarded by applying brakes at the rate of 2m per second square. it is stopped in 10 secs. find initial velocity
Answers
Answered by
188
a= -2 m/s²
t= 10 secs
According to 1st equation of motion,
v=u+at
So,
0=u+(-2*10)
or, u=2*10 =20 m/s
Answer: 20 m/s
t= 10 secs
According to 1st equation of motion,
v=u+at
So,
0=u+(-2*10)
or, u=2*10 =20 m/s
Answer: 20 m/s
Answered by
221
Hi there !!
Acceleration = a= -2 m/s²
Time = t= 10 secs
Initial velocity = u
Final velocity = v = 0
equation of motion :-
v = u+at
So,
0 = u+(-2 x 10)
u = 2 x 10
= 20 m/s
Initial velocity = 20 m/s
Acceleration = a= -2 m/s²
Time = t= 10 secs
Initial velocity = u
Final velocity = v = 0
equation of motion :-
v = u+at
So,
0 = u+(-2 x 10)
u = 2 x 10
= 20 m/s
Initial velocity = 20 m/s
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