Question

a car is running at 72km/h is slowed down to 18km/h by the application of breaks over a distance of 20m. The deceleration of car is​

Answer 1

Answer:

Heya Here's your answer mate

Given :-

• A car is running at 72km/h is slowed down to 18km/h by the application of breaks over a distance of 20m.

To Find :-

• Deceleration

Solution :-

• We know that

• 1 km/h = 5/18 m/s

• For Initial velocity

• 72 × 5/18 = 4 × 5 = 20 m/s

• For Final velocity

• 18 × 5/18 = 1 × 5 = 5 m/s

So now , Deceleration =

• 5² - 20² = 2a(20)

• 25 - 400 = 40a

• -375 = 40a

• -375/40 = a

• -9.375 = a

Acceleration = -9.375 m/s²

Gd evening

have a great day ahead

Answer 2

$hlo \: pari \: how \: r \: u \: hope \: u \: will\: be \\ f9 \: take care$ love u ❤️xD