Question

A car is running at a rate of 20m/sec. Suddenly, the driver applies brakes and stops the car in 5 secs. Find the value of acceleration of the car.

Answer 1

Given:

• Speed of car = 20 m/s
• The driver applies brakes & stops in 5s

To find:

• Acceleration of the car

Solution:

Here , the final velocity will be = 0 m/s because the driver applies brakes

Using the first kinematic equation

v = u + at

Where ,

• v : final velocity
• u : initial velocity
• a : acceleration
• t : time

→ 0 = 20 + a(5)

→ - 20 = 5a

→ a = -20/5

→ acceleration = - 4 m/s²

Note : -ve symbol indicates retardation

Hence , acceleration produced after applying brakes = - 4m/s²

Answer 2

Answer:

Given

u=20m/s

v=0

t=5

a=?

now

a=v-u/t

a=0-20/5

= -20/5

= -4

hence a= -4m s^-2

as the body is regarding the a is negative

hope it will help u

mark as brain list

Bhai Mera bad jo ans likha h usko 40like jabki vo galat h usna time Ko distance me use kiya h n Hamko 12 only what is this