Question

A car is running at a speed of 15 km h-1 while another similar car is moving at a speed of 45 km h-1. Find the ratio of their kinetic energies.

Answer 1

Hey!

This is a Abhiranjan raj helping you..

Speed of first car=15 km h-1.

Speed of second car =45 km h-1

so,

V1=15km h -1

V2=45 km h-1

then,
the ratio of both car of kinetic energy is

K(E)=1/2mv1^2.....

1/2*15^2.............(1)

K(E) =1/2mv2^2

=1/2*45^2

so, ratio is

K(E)/K(E)=1/2m*15×15/1/2m*45*45

1:9 Ans.

Hope it helps you

Answer 2

Answer:

1 : 9

Explanation:

just put the kinetic energy's formulae