A car is running on a straight road with accelerating motion. It travels 10 m distance in 3^ red second after the start and 12 m in 5^ th second. Now what distance does it travels in 8^ th second after its start?
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Answer: 35 meters
Explanation:we can use here the formula Snth=a/2(n-1)
so by this formula we can find value of a for 3rd second
putting value of n=3
a=10(by solving)
we again use this equation for 8th second
then we can find the value of distance in 8th second
that will come 35 meters
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