Question

A car is running on a straight road with accelerating motion. It travels 10 m distance in 3^ red second after the start and 12 m in 5^ th second. Now what distance does it travels in 8^ th second after its start?

Answer 1

Answer:     35 meters

Explanation:we can use here the formula   Snth=a/2(n-1)

so by this formula we can find value of a for 3rd second

putting value of n=3

a=10(by solving)

we again use this equation for 8th second

then we can find the value of distance in 8th second

that will come 35 meters

thanks

i hope that you got answer

Answer 2

Explanation:

i hope this will help you Thnx