Question

A car is running on a straight road with velocity of 126 km/h. It stops after travelling
a distance of 200 m Find retardation and time taken to stop the car.
​

Answer 1

Explanation:

given,

u=126km/h= 35m/s

v=0m/s

s=200m

v^2_u^2=2as

35^2=2×200×a

1225=400a

a=49÷16

= -3.62 m/s^2

v=u+at

0=35-3.62×t

35=3.62t

t=9.66 sec