Physics, asked by shubhamanand15112005, 3 months ago

a car is running with a velocity of 30 metre per second reaches Midway between two vertical parallel was separated by 360 m , when driver sounds the horn for a moment speed of sound in air is 330 m per second after blowing horn , the 3 echo will be heard by the driver respectively at​

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Answered by Anonymous
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Answered by Anonymous
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A car is running with a velocity of 30 metre per second reaches Midway between two vertical parallel was separated by 360 m , when driver sounds the horn for a moment speed of sound in air is 330 m per second after blowing horn , the 3 echo will be heard by the driver respectively at

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1.0s, 2.4s, 3.0s

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\leadsto \: X=30

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\star \: For \: the \: first \: echo

\leadsto\frac{180+180-x1}{330}=t1

\leadsto 360-30t1 = 330t1

\leadsto \: t1= \frac{360}{360}

\leadsto t1=1s

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\star \: For \: the \: second \: echo

\leadsto\frac{720+x2}{330}=t2

\leadsto720+30t2=330t2

\leadsto t2 \: \frac{720}{300}</p><p>

\leadsto t2=2.4s

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\star \: For \: the \: third \: second </p><p>

\leadsto\frac{1080-x3}{330}=t3

\leadsto1080-30t=330t3

\leadsto \: t3=3s

[Hope this helps you.../]

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