Question

A car is speeding up from 10m/s to 15m/s over a distance of 80m. What acceleration would be needed?

Answer 1

Answer:

inital velocity(v_0) 10m per sec.

final velocity (v) 15m per sec.

distance traveled (x) 80m

acceleration we have to find.so,

2ax= v^2-v_0^2

2ax= 225-100

2ax=125

a=125/160

a=0.78

i think this is right.

Answer 2

Answer:

v1 = 10m/s

v2 = 15m/s

s= 80m

v=v2-v1 = 15-10 = 5m/s

T = s/v = 80/5 = 16 sec.

•°• acceleration = v/T = (5/16)m/s^2