Question

A car is standing 200m behind the bus which is at rest .the two start moving at the same instant but with different forward acceleration .The bus has the acceleration of 2m/s^2 and the car has the acceleration of 4 m/s^2.The car will catch up with the bus after a time of?

Answer 1

Answer to this question is 10 seconds

Answer 2

Answer:

$10\sqrt{2}$

Explanation:(Important question-- jee mains-2019)

V elocity of car with respecyt to bus= 4-2=2m/s^2

Therefore we take up this acceleration for our further calculation.

Using the 3rd equation of motion

Intial velocity=0

(refer to the diagram pls)

200=12×2t^2

t=10√2 second