Question

A car is starting from rest,accelerate 5m/s^for 8sec along a straight line.If then it continues with constant velocity.calculate the distance travelled by the car at the end of 12secs,since it is started from rest.​

Answer 1

Answer:

320 m

Explanation:

For first 8 sec if car accelarates at the rate of 5m/s

Then distance travelled in first 8 sec is

S=ut +1/2at'2

S=1/2(5)(64)

S=160 m

Now,

Velicity attained by car after 8 sec

V=u+at

V=(5)(8)

V=40 m/s

Distance in next four seconds

D=st

D=(40)(4)

D=160 m

Total distance = 160+160= 320 m