a car is starting from rest accelerates at rate f through a distance s then continues at constant speed for time t and then decelerates at constant rate f/2 to come to rest if total distance is 15S then 1)s=ft (2) s=ft^2/6 (3)s=ft^2/48 (4)s=ft^2/72
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max20:
feel free to ask any doubt in any physics problem of any level
thankyou for your suggestion I'll try hard ik my basics are weak
i am trying to fix it
yes u hv to try. key factor of cracking jee is concepts. i struggled a lot with basics initially but after lot of hardwork and pain, finally i started loving physics
congratulation for clearing jee advanced
thanks a lot bro. i hv last suggestion. quit brainly now and focus on ur books. when u feel ur concepts are strong enough then rejoin it. Its just a suggestion
goodbye
i dont answer i ask my doubts here
if ur basics are clr u will be able to solve maxm of ur doubts
i think we have talked enough. Go and study
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