Question

a car is starting from rest and moves with a constant accleration of 2m/s find the velocity of the car after 10s​

Answer 1

Explanation:

Distance traveled in t0 seconds

S1=0×t0+21αt2(u=0 which is at rest)

Final velocity after t0 seconds,

Vs=0+αt0

Final velocity after applying retardation β=0

Initial velocity =final velocity after t0 seconds

0=(Vs)2−2β(s2) (s2 is the distance traveled after β retardation)

s2=2β(Vs)2

s2=2βα2t02

s1+s2=21αt02(α+βα)

=2βαt02(α+

Answer 2

Answer:

Here is your ans..

Explanation:

velocity of the car after 10 sec is

•20km/s

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