Question

A car is starts from rest if the acceleration of the car becomes 10 metre/second square after 20 seconds calculate final velocity and distance cover by the car.​

Answer 1

✬ Final Velocity = 200 m/s ✬

✬ Distance = 2000 m ✬

Explanation:

Given:

• Initial velocity of car is 0 m/s. ( Started from rest )
• Acceleration of car is 10 m/s².
• Time give is 20 seconds.

To Find:

• What is the final velocity and Distance covered by car ?

Formula to be used:

• v = u + at { for final velocity }
• s = ut + 1/2at² { for distance }

Solution: Let the final velocity be v. Using the first formula to find final velocity

$\implies{\rm }$ v = u + at

$\implies{\rm }$ v = 0 + 10(20)

$\implies{\rm }$ v = 200 m/s.

So, final velocity of car is 200 m/s.

[ To calculate distance use the second formula ]

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 0(20) + 1/2(10)(20)²

$\implies{\rm }$ s = 0 + 5(400)

$\implies{\rm }$ s = 2000 m

So, Distance covered by car is 2000m.

Answer 2

✬ Final Velocity = 200 m/s ✬

✬ Distance = 2000 m ✬

Explanation:

Given:

Initial velocity of car is 0 m/s. ( Started from rest )

Acceleration of car is 10 m/s².

Time give is 20 seconds.

To Find:

What is the final velocity and Distance covered by car ?

Formula to be used:

v = u + at { for final velocity }

s = ut + 1/2at² { for distance }

Solution: Let the final velocity be v. Using the first formula to find final velocity

⟹ v = u + at

⟹ v = 0 + 10(20)

⟹ v = 200 m/s.

So, final velocity of car is 200 m/s.

[ To calculate distance use the second formula ]

⟹ s = ut + 1/2at²

⟹ s = 0(20) + 1/2(10)(20)²

⟹ s = 0 + 5(400)

⟹ s = 2000 m

So, Distance covered by car is 2000m.