Question

A car is traveling along a straight road at a velocity of +36.0 m/s when its engine cuts out. For the next twelve seconds the car slows down , and its average acceleration is ā1 . For the next six seconds the car slows down further, and its average acceleration is ā 2 . The velocity of the car at the end of the eighteen-second period is +28.0 m/s. The ratio of the average acceleration values is ā1 / ā2 = 1.50. Find the velocity of the car at the end of the initial twelve-second interval.

Topic : - Kinematics 1d
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Answer 1

Answer:

12.5m/s

Explanation:

s1 = 40 km, s2 = 50 km,

Total distance = 40 + 50 = 90 km, Total time = 1+1 = 2 Hr.

Avg. Speed = Total distance/ total time = 90 / 2 = 45 km/h.

45 km/h= 45 x 5/18 = 12.5 m/s.

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Answer 2

Answer:

30m/sec

Explanation:

Refer attachment