A car is traveling at 20m/s along a road. a child runs out into the road 50 m ahead and the car driver steps on the pedal break. what must the car deacceleration be if the car is to stop just before it teaches the child.
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u ( INITIAL VELOCITY ) = 20 m/ sec
s ( DISTANCE ) = 50 m
v ( Final Velocity ) = 0 m/sec since car has to stop
Using 3rd equation of motion :
v square = u square + 2 as
0 square = 20 square + 2 * a * 50
0 = 400 + 100a
- 400 = 100 a
=> a = 400 / 100
=> a = 4 m / sec square
ANSWER = 4 m / sec square
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s ( DISTANCE ) = 50 m
v ( Final Velocity ) = 0 m/sec since car has to stop
Using 3rd equation of motion :
v square = u square + 2 as
0 square = 20 square + 2 * a * 50
0 = 400 + 100a
- 400 = 100 a
=> a = 400 / 100
=> a = 4 m / sec square
ANSWER = 4 m / sec square
HOPE IT HELPS :):):):):):)
MARK AS BRAINLIEST
Priya12345678:
It's 4m/s square
NOW OK !!!!
yes
thanks
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