Question

A car is traveling at 36km/h if its velocity increase to 72km/h in 5s then find the acceleration of the car in SI units​

Answer 1

Answer:

a = v-u/t

Explanation:

a= 72-36/5

a = 36/5

a=7.2

Answer 2

SOLUTION:-

Given:

A car is traveling at 36km/h.

Velocity = 72km/h

Time = 5 second.

To find:

Acceleration.

Solution:

Initial velocity= 36km/h

We convert in m/s.

So,

$= > \frac{36000}{3600} \\ \\ = > 10m/ s$

And,

Final velocity= 72km/h

We convert in m/s.

So,

$= > \frac{72000}{3600} \\ \\ = > 20m /s$

Now,

We know that, acceleration is;

=) a=(v-u)/t

Therefore,

$= > a = \frac{(v - u)}{t} \\ \\ = > a = \frac{(20 - 10)?}{5} \\ \\ = > a = \frac{10}{5} \\ \\ = > a = 2m/ {s}^{2}$

Hope it helps ☺️