Question

A car is traveling at 72km/h and when the breaks are applied it expands a uniform retardation of 2ms-2.how long does it takes he car to stop and how far does it travel from the intants the breaks are applied.

Answer 1

Hey Mate! here is your answer .

u = 72km/h = 20m/sec.
v = 0
a = 2m/s^2

=> first calculate the time.
v = u + at
0 = 20 + (-2)×t
0 = 20 - 2t
2t = 20
t = 10 sec.


=> now calculate the distance.
S = ut + 1/2 at^2
S = 20*10 + 1/2*2*(10)^2
S = 200 + 100
S = 300m ――――> ANS.........

I HOPE THIS HELPS.......☺️
#YASH
HAVE A GOOD DAY!!

Answer 2

u=72*1000/60*60=20m/s
v=0m/s
t=-20/2
t=10sec