Question

A car is traveling with a speed of 22 m/s. The brakes can produce a maximum deceleration of 8.0 m/s. What is the minimum stopping distance for the car?​

Answer 1

⚘ Given That :

• ⇒ Initial Velocity of Car (u) = 22m/s
• ⇒ Final Velocity of Car (v) = 0m/s
• ⇒ Deceleration of Car (a) = [ - 8m/s ]

⚘ Need To Find :

• ➣ Minimum stopping distance for the car ?

★ Formula Used Here :

• ➟ v² = u² + 2as

✇ Where :

• ↣ v = Final Velocity
• ↣ u = Initial Velocity
• ↣ a = acceleration
• ↣s = minimum Stopping distance

____________________

✪ Putting Value in Formula :

• ➻ v² = u² + 2as
• ➻ (0)² = (22)² + 2 × (- 8) × s
• ➻ 0 = 484 - 16s
• ➻ - 484 = - 16s

◆ [ Cancelling -ve sign both sides ]

• ➻ 484 = 16s
• ➻ 484 / 16 = S
• ➻ Min. Stopping Distance = 30.25m

☢ Hence :

• » Minimum stopping distance for car is 30.25m

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