a car is travelling along the road at 36 km per hour it accelerates at 1 m per second square for a distance of 22 m. how fast is it then traveling also calculate the time taken to cover this distance.
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u = 36 km/hr = 36 * (5/18) = 10 m/s
v = 72 km/hr = 20 m/s
Using Newton's first eqn. of motion :
v = u + at
20 = 10 + a(5)
Hence a = 2 m/s²
Now the car stops in 20 seconds :
Using the same equation :
v = 0
u = 20 m/s
t = 20 sec
a = ?
0 = 20 + a (20)
a = -1 m/s²
In 2nd case there is retardation of 1 m/s²
v = 72 km/hr = 20 m/s
Using Newton's first eqn. of motion :
v = u + at
20 = 10 + a(5)
Hence a = 2 m/s²
Now the car stops in 20 seconds :
Using the same equation :
v = 0
u = 20 m/s
t = 20 sec
a = ?
0 = 20 + a (20)
a = -1 m/s²
In 2nd case there is retardation of 1 m/s²
anutreasa950:
How did you get v as 72 km per hour?
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