Question

A car is travelling along the road at 8 m/s. It accelerates at 1 m/s^2 for a distance of 18 m. How fast is it then travelling ?

Answer 1

$u = 8 \: ms {}^{ - 1}$

$a = 1 \: {ms}^{ - 2}$

$s = 18 \: m$

$v = to \: befound$

using 3rd equation of motion

v^2=u^2 + 2as

v^2= 64 + 2×1×18

v^2= 64 + 36

v^2=100

v= 10 m/s

Answer 2

Answer:

it is then travelling 2m/s faster than earlier as V- U = 2