Question

A car is travelling along the road at 8m s-¹.It accelerates at 1 ms-² for a distance of 18m.How fast is it then travelling?​

Answer 1

Initial speed u=8 m/s

Initial speed u=8 m/s Acceleration a=1 m/s

Initial speed u=8 m/s Acceleration a=1 m/s 2

Initial speed u=8 m/s Acceleration a=1 m/s 2

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 m

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aS

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8 2

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8 2 =2×1×18

Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8 2 =2×1×18⟹ v=10 m/s

hope it helps you

Answer 2

ANSWERS:

Initial speed u=8 m/s

$Acceleration \: \: a={1 m/s}^{2}$

Distance S=18 m

$Using \: {v}^{2} − {u}^{2} =2aS$

$Or \: \: {v}^{2} − {8}^{2} =2×1×18$

⟹ v=10 m/s