Question

A car is travelling along the road at 8m/s it accekerates at 1m/s for a distance of 18m how far it is then travelling

Answer 1

Hi friend,

Solution :-
U= 8m/s

A = 1m/s^2

S = 18M

So, V^2 - U^2 = 2AS
Or, v^2= 2as + u^2
Or, v^2 = 2×1×18+8^2
0r, v^2 = 36 + 64
Or, v^2 = 100
Or, v = 10m/s^2

Thus, the car is travelling 10m/s after 18M...i hope it helps you


Mark me as a brainlist...

Answer 2

ANSWER:-

It is given that ,

Initial velocity ( u ) = 8m/s

Acceleration ( a ) = 1m/s^2 and

Distance ( S ) = 18 m

By using the equation , 2as = v^2 - u^2

Now , putting values of s , u , and a in the equation

2 × 1 × 18 = v^2 - 64

36 = v^2 - 64

36 + 64 = v^2

100 = v^2

Now , we don't want the value of v^2 but v . Hence , for that we do Square Rooting Both sides

√100 = √v^2

10 = v

THANKS!!!