Question

a car is travelling along the road at 8m s.It accelerates at 1m s^2 for a distance of 18 m.How fast is the car travelling

Answer 1

Howdy!!
Your answer is--

Given, initial velocity u = 8m/s
acceleration a = 1m/s^2
& distance s = 18meter
So, according to formula

v^2 = u^2 + 2as
=> v^2 = 8^2 + 2×18×1

=> v^2 = 64+36

=> v^2 = 100

=> v = 10m/s


Hence, its final velocity is 10m/s


Hope it help you

Answer 2

Heya
U=8m/s
a=1m/s²
s=18m
v²-u²=2as
v²=2as+u²
v²=2×1×18+8²
v²=36+64
v²=100
v=10m/s
The car is traveling at 10 m/s after 18 m.