A car is travelling at 20 m / s along a road. A child runs out into the road 50 m ahead and the car driver steps on the brake pedal. What must the car's declaration be if the car is to stop just before it reaches the child. ?
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Answer:
4 m/s^2
Explanation:
According to the given question,
v = final velocity = 0 m/s
u = initial velocity = 20 m/s
s = displacement = 50 m
a = acceleration/deceleration =?
And we are asked to find the deceleration of the car such that it wont hit the child.
We know,
- v^2 = u^2 +2as
(Putting the values)
- 0 = 400 + 2×a×50
- a = -(400/100)
- a = -4 m/s^2 ans.
(The negative sign shows that its decelerating whereas the 4 m/s^2 is its magnitude)
So the car needs the deceleration of 4 m/s^2 such that it wont hit the child.
Anonymous:
Thanks
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