Question

A car is travelling at 20 m/s. It makes an emergency stop to avoid hitting a badger in the road. If the car has a mass of 1000 kg and it travels 48 m before it comes to a stop, how much braking force did the driver apply?

Answer 1

Answer:

Please refer to the attachment

Explanation:

Answer 2

Braking force = -4166 N

Explanation:

• Force applied to stop the car is equal and opposite to the frictional force offered by the ground.
• Frictional force is the force which make the hindrance in the path of moving body, it always opposes the the motion of body and is the loss of energy exerted by the moving body

Given, initial velocity = 20 m/s

final velocity = 0 m/s

mass of body = 1000 kg

distance traveled = 48 m

=> Force = mass * acceleration

=> F = m a

we can use the following equation of motion to calculate the acceleration of the car

=> v² - u² = 2 as

=> a = $\frac{v^{2}-u^{2} }{2s}$

=> a = $\frac{0^{2}-20^{2} }{2*48}$

=> a = $\frac{-200 }{48}$

=> a = - 4.166 ms⁻²

=> Force = mass * acceleration

=> F = 1000 * (-4.166)

=> F = - 4166 N

-4166 N is the force exerted while brakes applied

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