Question

A car is travelling at 20 m/s. It makes an emergency stop to avoid hitting a badger in the road. If the car has a mass of 1000 kg and it travels 48 m before it comes to a stop, how much braking force did the driver apply? Use the equations below to help you and give your answer to the nearest hundred.

Answer 1

Answer:

Ok here is your answer

Explanation:

Bye

Answer 2

Answer:

Initial velocity,u = 20m/s

Final velocity,v = 0

Mass of car, m = 1000 kg

Distance ,s = 48m

So, force = ?

By using second equation of motion,

v^2 - u^2 = 2as

(0)^2 - (20)^2 = 2a× 48

0-400 = 96 × a

-400 = 96× a

a = -400/96

a= -25/6

Using Newton's second law of motion,

F = ma = 1000× -25/6

F= -25000/6

F = - 4166.66 or - 4166.6

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